1/x^2+1/(4x)^2=1/196

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Solution for 1/x^2+1/(4x)^2=1/196 equation: 



1/x^2+1/(4x)^2=1/196

We move all terms to the left:

1/x^2+1/(4x)^2-(1/196)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

1/x^2+1/4x^2-(+1/196)=0

We get rid of parentheses

1/x^2+1/4x^2-1/196=0

We calculate fractions

We do not support expression: x^4

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